More maths nerdness, where 1 Amp = 1 Coulomb/sec
View attachment 4253
Here the drain curve has been inverted and marked to show hashed areas under the curve. When these areas are calculated and added together they represent the amount of electrical charge in Coulombs that has been drained from the 12V battery during the 15 minute period, approx. 395 Coul.
In one hour x4 =~ 1600 Coul; one day ~ 38400 Coul.
The battery of this test started at less than 12V, which indicates it was depleted to begin with, e.g. 11.96V corresponds to about 40% SOC.
The laef uses a 35A-hr (20hr rate) battery which would be about 126,000 Coulombs when full, and 50400 Coul when at 40%. So it was depleted in about 1.3 days.
Water Analogy:
Substitute liters for Coulombs